The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
Learn more about extraneous solution on:
https://brainly.com/question/295656
#SPJ4
Answer:
its not d! its a -8
Step-by-step explanation:
