A steel hex nut has two regular hexagonal faces and a hole with a diameter of 0.4 cm through the middle. its mass is 3.03 grams. a regular hexagonal prism is shown. a cylinder is cut out of the middle of the prism. the hexagon has an apothem with length 0.5 centimeters. the base edges have lengths of 0.6 centimeters and the height of the prism is 0.5 centimeters. the cylinder has a diameter of 0.4 centimeters. complete the steps to calculate the density of the steel. calculate the volume of the prism. recall that the area of a hexagon is one-half times the apothem times the perimeter. v = cm3 calculate the volume of the cylinder. round to the nearest hundredth. v = cm3 find the volume of the composite figure. v = cm3 calculate the density by dividing the mass by the volume. d = g/cm3

Respuesta :

The density that's gotten by dividing the mass by the volume is 0.91.

How to calculate the density?

From the information given, the volume of the cylindrical hole will be:

= πr²h

= 3.14 × (0.4/2)² × 1

= 0.1256

The volume of the pyramid will be:

= 1/3 × A × h

= 1/3 × 6✓3 × 1

= 3.4641

The difference will be:

= 3.4641 - 0.1256

= 3.3385.

The density of the figure will be:

= Mass / Volume

= 3.03/3.3385

= 0.91

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Answer:

Calculate the volume of the prism. Recall that the area of a hexagon is One-half times the apothem times the perimeter.

V = ✔ 0.45 cm3

Calculate the volume of the cylinder. Round to the nearest hundredth.

V = ✔ 0.06 cm3

Find the volume of the composite figure.

V = ✔ 0.39 cm3

Calculate the density by dividing the mass by the volume.

d = ✔ 7.77 g/cm3

Step-by-step explanation:

just did it (edg 2022)