The amount of heat that is required to melt 22g piece of ice at -8 degrees to water at 14 degrees is 1,011.56 Joules.
How do we calculate the required heat?
Required amount of heat will be calculated by using the below equation as:
Q = mcΔT, where
m = mass = 22g
c = specific heat of ice = 2.09 J/g. degree C
ΔT = change in temperature = 14 - (-8) = 22 degree C
On putting all values, we get
Q = (22)(2.09)(22) = 1,011.56 J
Hence required amount of heat is 1,011.56 J.
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