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in a bag of candy, the probabilities that an orange candy is chosen is 0.55 and the probability that a green is chosen is 0.45. a person reaches into the bag of candy and chooses two. if X is the number of green candy pieces chosen, find the probability that has 0, 1, or 2 green pieces chosen.

(a) draw a tree diagram showing the possibilities for each outcome

(b) create the binomial distribution table for P (X)


Respuesta :

MrRoyal

If X is the number of green candy pieces chosen, the binomial table that describes the probability is:

X         0               1               2

P(X)    0.3025    0.4950     0.2025

The tree diagram

The probabilities are given as:

  • P(Orange) = 0.55
  • P(Green) = 0.45

Represent the orange candy with letter O, and green candy with letter G

Using the above representations, see attachment for the tree diagram

The binomial distribution table

From the diagram in (a), we have the following sample space:

GG, OG, OG, OO

So, the frequency table is:

GG = 1

OG = 2

OO = 1

The probabilities are then calculated as:

GG = 0.45 * 0.45 = 0.2025

OG = 2 * 0.55 * 0.45 = 0.4950

OO = 0.55 * 0.55 = 0.3025

Hence, the binomial table is:

X         0               1               2

P(X)    0.3025    0.4950     0.2025

Read more about probabilities at:

https://brainly.com/question/251701

#SPJ1

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