A golfer hit a golf-ball from the top of a building 25 ft off the ground with an initial velocity of 45 feet per second. What is the maximum height that the golf ball will reach?

Respuesta :

Answer:

The maximum height is 180 feet

Step-by-step explanation:

Answer:

56.641 feet

Step-by-step explanation:

Use the equation [tex]h(t)=-16t^2+v_0t+h_0[/tex] to find the vertical distance of an object travelling at a speed of [tex]v_0\text{ft}/\text{s}[/tex] at initial height [tex]h_0\text{ft}[/tex] after [tex]t[/tex] seconds.

First, we find the time at which the ball will reach maximum height:

[tex]t=-\frac{b}{2a}\\\\t=-\frac{45}{2(-16)}\\ \\t=-\frac{45}{-32}\\\\t=\frac{45}{32}\approx1.406[/tex]

Second, we find the vertical distance of the ball after [tex]t=\frac{45}{32}[/tex] seconds:

[tex]h(\frac{45}{32})=-16(\frac{45}{32})^2+45(\frac{45}{32})+25=56.641[/tex]

Therefore, the golf ball will reach a maximum height of 56.641 feet after 1.406 seconds.