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ethyl chloride, c2h5cl, is used as a local anesthetic. it works by cooling tissue as it vaporizes; its heat of vaporization is 26.4 kj/mol. how much heat could be removed by 20.0 g of ethyl chloride?

Respuesta :

The amount of heat that could be removed by 20.0 g of ethyl chloride is 8.184 kJ.

How do we calculate required heat?

Required amount of heat which can be removed for the vaporization will be calculated as:

Q = (n)(ΔHv), where

  • n = moles of ethyl chloride
  • ΔHv = heat of vaporization = 26.4 kj/mol

Moles will be calculated as:

n = W/M, where

  • W = given mass of ethyl chloride = 20g
  • M = molar mass of ethyl chloride = 64.51 g/mol

n = 20 / 64.51 = 0.31 mol

On putting all these values in the above equation, we get

Q = (0.31)(26.4) = 8.184 kJ

Hence involved amount of heat is 8.184 kJ.

To know more about heat of vaporization, visit the below link:

https://brainly.com/question/13106213

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