8. How much heat, in kilojoules, is needed to produce 1850 grams of ammonia (NH3),
according to the following reaction?
2 N2 + 6 H2O → 4 NH3 + 3 02
AH = + 1530 kJ

Respuesta :

Based on the enthalpy of the reaction, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).

What is heat of reaction?

The heat of reaction or enthalpy change is the heat absorbed or evolved when reactant molecules react to form products.

According the enthalpy value of the reaction, 4 moles of ammonia require 1530 kJ of heat for its formation.

Molar mass of ammonia = 17 g

Mass of 4 moles of ammonia = 4 × 17 = 68 g

1850 g of ammonia will require = 1850 × 1530/68 = 41625 kJ of heat.

Therefore, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).

Learn more about enthalpy at: https://brainly.com/question/14047927

#SPJ1