(a) The amplitude of the wave is 3 cm.
(b) The speed of the wave is 19.6 m/s
(c) The angular frequency is 653.72 rad/s.
(d) The period of the wave is 0.0096 s.
(e) The wavelength of the wave is 0.392 m.
The speed of the wave is calculated as follows;
[tex]v = \sqrt{\frac{T}{\mu} }[/tex]
where;
[tex]v = \sqrt{\frac{50}{0.13} } \\\\v = 19.6 \ m/s[/tex]
ω = v/r
ω = v/A
ω = 19.6/0.03
ω = 653.72 rad/s
[tex]T = \frac{2\pi }{\omega } \\\\T = \frac{2\pi }{653.72} \\\\T = 0.0096 \ s[/tex]
v = fλ
λ = v/f
λ = 19.6/50
λ = 0.392 m
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