Answer:
[tex]\circ\ \ 36\sqrt{3}[/tex]
Step-by-step explanation:
[tex]CD=12\times \sin(60) =12\times \frac{\sqrt{3} }{2}[/tex]
Important Note:………………………………………………………………………………………
ABC is an equilateral triangle because it has 2 angles of measure 60
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According to the note AB = 12
Final answer :
[tex]\text{Area of triangle ABC} =\frac{AB\times CD}{2}[/tex]
[tex]=\frac{12\times 6\sqrt{3} }{2}[/tex]
[tex]=\frac{72\sqrt{3} }{2}[/tex]
[tex]=36\sqrt{3}[/tex]
