Answer:
1; 1.5; 3.
Step-by-step explanation:
1) the potential zeros are the numbers which the '-9' can be divided by: ±1; ±3; ±9;
2) according to the definition above: x=1. Then the given equation can be re-written
2x³-11x²+18x-9=0; ⇔ (x-1)(2x²-9x+9)=0. Then
3) re-written again as
[tex](x-1)(x-\frac{3}{2})(x-3)=0;[/tex]
4) the required zeros are: 1; 1.5 and 3.
