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A body of mass m, = 0.050 kg and initial velocity v₁ = 9 m / s turned to the right collides with a body of mass m₂ = 0.030 g with unknown initial velocity v₂. After the collision, the two bodies join together and have a final velocity vy = 6 m / s to the right. Using the momentum conservation theorem, find the initial velocity v₂

Respuesta :

Answer:

1 m/s

Explanation:

Po = Pf

(0.050kg)(9 m/s) + (0.030kg)(v2) = (0.05kg + 0.030)(6 m/s)

0.45 kgm/s + (0.030kg)(v2) = 0.48 kgm/s

(0.030kg)(v2) = 0.03 kgm/s

v2 = 1 m/s

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