Respuesta :

charliethebest2002

Answer:

  • [tex]\boxed{\sf{y=-\dfrac{-2x+6}{3} }}[/tex]

Step-by-step explanation:

Given:

  • Isolate the term of x and y from one side of the equation.

To find:

  • The value of y.

Solutions:

-3y+1=7-2x

First, you have to subtract by 1 from both sides.

[tex]\Longrightarrow: \sf{-3y+1-1=7-2x-1}[/tex]

Solve.

[tex]\Longrightarrow: \sf{-3y=-2x+6}[/tex]

Then, you divide by -3 from both sides.

[tex]\Longrightarrow: \sf{\dfrac{-3y}{-3}=-\dfrac{2x}{-3}+\dfrac{6}{-3}}[/tex]

Solve.

Divide these numbers from left to right.

[tex]\Longrightarrow: \sf{-\dfrac{2x}{-3}+\dfrac{6}{-3}}[/tex]

[tex]\Longrightarrow: \sf{\dfrac{-2x+6}{-3}}[/tex]

[tex]\Longrightarrow: \sf{=-\dfrac{-2x+6}{3}}[/tex]

[tex]\Longrightarrow: \boxed{\sf{y=-\dfrac{-2x+6}{3}}}[/tex]

[tex]\text{Therefore, the correct answer is {y=-$\dfrac{-2x+6}{3}$}}}}[/tex].

I hope this helps, let me know if you have any questions.

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