Using it's concept, it is found that there is a 0.0333 = 3.33% probability of choosing a B not replacing it and then choosing a vowel.
A probability is given by the number of desired outcomes divided by the number of total outcomes.
The word basketball has 10 letters.
Thus, the probability of choosing a B not replacing it and then choosing a vowel is given by:
[tex]P(A \cap B) = P(A)P(B|A) = 0.1 \times 0.3333 = 0.0333[/tex]
More can be learned about probabilities at https://brainly.com/question/14398287