Given circle E with diameter \overline{CD} CD and radius \overline{EA} EA . \overline{AB} AB is tangent to E at A. If EA=18 and DB=12, solve for AB. Round your answer to the nearest tenth if necessary.

Respuesta :

The line AB from the diagrammatic expression of the tangent of the circle shows that line AB is 24.0

What is the tangent of a circle?

A tangent of a circle is a line that intersects the circle at a single point. The site at which the tangent intersects the circle is referred to as the site of tangency.

From the given information:

  • Line |CD| =  Diameter
  • Line |EA| = radius = 18
  • Line |DB| = 12

Then, we can infer that line EA = DE since they are both (radii of the circle.)

  • Line |DE| = |EA| = 18

By using the formula for Pythagoras theorem, we can find line |EA|.

  • hyp² = opp² + adj²

where;

  • Line |BE| = hypotenuse = DB + BE = 12 + 18 = 30
  • Line |AB| = opposite (x) = ???
  • Line |EA| = adjacent = 18

Thus;

30² = x² + 18²

900 = x² + 324

-x²  = -900 + 324

x  = √576

x = 24.0

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