Answer:
y=2x-5
Step-by-step explanation:
Hi there!
We are given that a line has a slope of 2, and passes through the point (4,3)
We want to use point-slope form to find this equation of the line, yet we want to write this in slope-intercept form
Point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point
As we are already given the slope and a point, we can substitute these values into the formula to find the line.
First, substitute 2 as m in the equation:
[tex]y-y_1=2(x-x_1)[/tex]
Now substitute 4 as [tex]x_1[/tex] and 3 as [tex]y_1[/tex]
[tex]y-3=2(x-4)[/tex]
This is the equation of the line in point-slope form.
Now we need to write it in slope-intercept form
Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept
We can actually get to slope-intercept form from point-slope form.
First, distribute 2 to both x and -4 on the right side
y-3=2x-8
Now add 3 to both sides
y=2x-5
Hope this helps!