Answer: [tex]log (x^3y )[/tex]
Step-by-step explanation:
First we want to make the coefficients of the log the exponents of what is in the log
[tex]3 log (x) + 2 log (y) - log (y)\\log (x^3) + log (y^2) - log (y)[/tex]
Now adding two log with the same base is the same as multiplying what you are taking the log of
[tex]log (x^3) + log (y^2) - log (y)\\log (x^3y^2) - log (y)[/tex]
Now subtracting two logs with the same base is the same as dividing what you are taking the log of
[tex]log (x^3y^2) - log (y)\\log (\frac{x^3y^2}{y} )[/tex]
Now we simplify
The [tex]y^2[/tex] cancels out the y in the denomiator
[tex]log (x^3y^2) - log (y)\\log (x^3y )[/tex]
