Answer:
0.64
Step-by-step explanation:
Given the sides of a triangle, we can solve for any angle using the Law of Cosines: [tex]a^2=b^2+c^2-2bc(cosA)[/tex]
Our variables:
a = 27
b = 36
c = 45
B = 90°
[tex]a^2=b^2+c^2-2bc(cosA)[/tex]
[tex](27)^2=(36)^2+(45)^2-2(36)(45)(cosA)[/tex]
[tex]720=1296+2025-3240(cosA)[/tex]
[tex]720-3321=-3240(cosA)[/tex]
[tex]-2601=-3240(cosA)[/tex]
[tex]\frac{2601}{3240} =cosA[/tex] ≈ [tex]0.80278[/tex]
[tex]cos^-(A)=cos^-(\frac{2601}{3240})[/tex]
[tex]< A = 0.63885708[/tex]
This might be wrong, but you get the method. I would repost for a better answer from someone else because I'm practically half asleep. Very sorry but I hope you get some help soon! Best of luck
