Answer:
0.2248307402
Step-by-step explanation:
Let 'success', p = 0.16,
and 'failure', q = 1 - 0.16 = 0.84
and the number of trials, n = 7
r = 2
[tex]P(X = r) = \binom{n}{r} {p}^{r} {q}^{n - r} \\ P(X = 2) = \binom{7}{2} {(0.16)}^{2} {0.84}^{5 - 2} \\ = 0.2248307402[/tex]
