Hi there!
Recall Faraday's Law:
[tex]\epsilon = N\frac{d\Phi_B}{dt}[/tex]
ε = Induced emf (V)
N = Number of Loops
φ = Magnetic Flux (Wb)
t = time (s)
Thus, the induced emf is equivalent to the number of loops of the coil times the rate of change of the magnetic flux bounded by the area of the coil, so:
[tex]\epsilon = 2 \cdot \frac{47 - (-65)}{0.38} = 2 \cdot \frac{112}{0.38} = 589.47V =\boxed{ 5.9 \times 10^2 V}}[/tex]
**This is the magnitude of the induced emf. With Lenz's Law, however, the answer would be negative, which just indicates it is a resistive emf.
