If the radius of a sphere is increasing at the constant rate of 3 centimeters per second, how fast is the volume changing when the surface area is 10 square centimeters

Respuesta :

How fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.

To solve the question, we need to know the volume of a sphere

Volume of a sphere

The volume of a sphere V = 4πr³/3 where r = radius of sphere.

How fast the volume of the sphere is changing

To find the how fast the volume of the sphere is changing, we find rate of change of volume of the sphere. Thus, we differentiate its volume with respect to time.

So, dV/dt = d(4πr³/3)/dt

= d(4πr³/3)/dr × dr/dt

= 4πr²dr/dt where

  • dr/dt = rate of change of radius of sphere and
  • 4πr² = surface area of sphere

Given that

  • dr/dt = + 3 cm/s (positive since it is increasing) and
  • 4πr² = surface area of sphere = 10 cm²,

Substituting the values of the variables into the equation, we have

dV/dt = 4πr²dr/dt

dV/dt = 10 cm² × 3 cm/s

dV/dt = 30 cm³/s

So, how fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.

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