A disk whose rotational inertia is 450 kg.m2 hangs from a wire whose torsion constant is 2300 N.m/rad. When its angular displacement is -0.23 rad, what is its angular acceleration

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Fact2730 Fact2730

14-04-2022
Physics

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A disk whose rotational inertia is 450 kg.m2 hangs from a wire whose torsion constant is 2300 N.m/rad. When its angular displacement is -0.23 rad, what is its angular acceleration

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okpalawalter8 okpalawalter8 · Answer 1 · 2022-04-26T12:49:07+02:00

For a disk whose rotational inertia is 450 kg.m2 hangs from a wire whose torsion constant is 2300 N.m/rad, the angular acceleration is mathematically given as

a = 1.176 rad/s^2

What is its angular acceleration?

Generally, the equation for the angular acceleration is mathematically given as

a = torsion constant x theta/inertia

therefore,

a = 2300 x 0.23/450

a = 1.176 rad/s^2

In conclusion, the angular acceleration is

a = 1.176 rad/s^2