Respuesta :
The true solution of the logarithmic equation [tex]\ln e^{\ln x} + \ln e^{\ln x^2} = 2\ln 8[/tex] will be 4.
What is a logarithm?
Logarithms are another way of writing exponent. A logarithm with a number base is equal to the other number. It is just the opposite of the exponent function.
The logarithmic equation is given as
[tex]\ln e^{\ln x} + \ln e^{\ln x^2} = 2\ln 8[/tex]
We know that the formula
[tex]\ln e = 1\\\\\ln b^a = a \ln b\\\\\ln a + \ln b= \ln a +b[/tex]
Then we have
[tex]\begin{aligned} \ln x \times \ln e + \ln x^2 \times \ln e = \ln 8^2\\\\\ln x + \ln x^2 = \ln 64\\\\\ln x*x^2 = \ln 64 \end{aligned}[/tex]
Then take antilog, then we get
[tex]\rm x^3 = 64\\\\x^3 = 4^3 \\\\x \ =4[/tex]
More about the logarithm link is given below.
https://brainly.com/question/7302008
