Answer:
4x²+20x+16=0
Step-by-step explanation:
First we can expand the right side:
[tex](2x+4)(2x+7) = 4x^{2} +8x+14x+28[/tex]
Simplify:
[tex]4x^{2} +26x+28[/tex]
Now we can expand the left side:
[tex]3(2x+4) = 6x+12[/tex]
Now we equate both of them to each other:
[tex]4x^{2} +26x+28= 6x+12[/tex]
To make this into a quadratic form we can subtract 6x+12 from both sides:
[tex]4x^{2} +26x+28 - (6x+12) = 6x+12- (6x+12)[/tex]
Simplify
[tex]4x^{2} +20x+16 = 0[/tex]
This is the equation in most simplified version.
