Step-by-step explanation:
[tex]triangle \: abd \\ using \: pythagoras \: theorem \\ {hyp}^{2} = {adj}^{2} + {opp}^{2} \\ {12}^{2} = {3}^{2} + {opp}^{2} \\ 144 = 9 + {x}^{2} \\ 144 - 9 = {x}^{2} \\ 135 = {x}^{2} \\ take \: the \: square \: of \: both \: sides \\x = 11.62[/tex]
using the opposite side of triangle and
[tex]using \: pythagoras \: theorem \\ {16}^{2} = {11.62}^{2} + {x}^{2} \\ 256 = 135.02 + {x}^{2} \\ 256 - 135.02 = {x}^{2} \\ 120.198 = {x}^{2} \\ take \: the \: roots \: of \: both \: sides \\ x = 10.96[/tex]
therefore the length of line AC
[tex] = 3 + 10.96 \\ = 13.96[/tex]
hope this helps
