Respuesta :

fieryanswererft

Answer:

8.6 mile

Explanation:

[tex]\sf equation \ follows : \ \ \ d = 1.2116\sqrt{h}[/tex]

  • d represents the distance a person can see.
  • h represents the height above the ocean.

what the captain sees:

[tex]\hookrightarrow \sf d_c = 1.2116\sqrt{15}[/tex]

what the sailor sees:

[tex]\hookrightarrow \sf d_s = 1.2116\sqrt{120}[/tex]

Difference between them:

[tex]\sf \rightarrow 1.2116\sqrt{120} \ - \ 1.2116\sqrt{15}[/tex]

[tex]\sf \rightarrow 8.58[/tex]

[tex]\sf \rightarrow 8.6[/tex]      (rounded to nearest tenth)

semsee45

Answer:

8.6 miles (nearest tenth)

Step-by-step explanation:

[tex]d=1.2116\sqrt{h}[/tex]

where:

  • d = approximate distance a person can see (in miles)
  • h = person's height above the ocean (in feet)

Captain

Given the Captain is 15 ft above the ocean:

[tex]\implies h = 15[/tex]

Substituting this into the equation:

[tex]\implies d_1=1.2116\sqrt{15}[/tex]

Lookout

Given the lookout is 120ft above the ocean:

[tex]\implies h = 120[/tex]

Substituting this into the equation:

[tex]\implies d_2=1.2116\sqrt{120}[/tex]

Solution

To find how much farther the lookout can see than the captain, subtract the distance the captain can see from the distance the lookout can see:

[tex]\implies d_2-d_1[/tex]

[tex]\implies 1.2116\sqrt{120}-1.2116\sqrt{15}[/tex]

[tex]\implies 1.2116(\sqrt{120}-\sqrt{15})[/tex]

[tex]\implies 8.579906391...[/tex]

[tex]\implies 8.6\: \sf miles\:(nearest\:tenth)[/tex]

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