Respuesta :
The Bruce must include X and Z in his report.
We have given the data on four electric circuits listed in the table
For w :
Voltage, V=18\ V
resistance, [tex]R=38\ \Omega[/tex]
What is the formula for ohm's low?
The formula of Ohm's low is V=IR
[tex]I=\dfrac{V}{R}[/tex]
[tex]I=\dfrac{18\ V}{38\ \Omega}[/tex]
I=0.47
[tex]q=0.47\times8[/tex]
So charge,q=It
q=3.76\ C
For x :
Voltage, V=24\ V
[tex]resistance, R=34\ \Omega[/tex]
so, V=IR...(Ohm's low)
[tex]I=\dfrac{V}{R}[/tex]
[tex]I=\dfrac{24\ V}{34\ \Omega}[/tex]
I=0.705
[tex]q=0.705\times8[/tex]
So charge,q=It
q=5.64\ C
For y :
Voltage, V=34\ V
resistance, [tex]R=70\ \Omega[/tex]
so, V=IR.......(Ohm's low)
[tex]I=\dfrac{V}{R}[/tex]
[tex]I=\dfrac{34\ V}{70\ \Omega}[/tex]
I=0.485
[tex]q=0.485\times8[/tex]
So charge,q=It
q=3.88\ C
For z :
Voltage, V=12\ V
resistance, [tex]R=18\ \Omega[/tex]
so, V=IR......(Ohm's low)
[tex]I=\dfrac{V}{R}[/tex]
[tex]I=\dfrac{12\ V}{18\ \Omega}[/tex]
I=0.66
[tex]q=0.66\times8[/tex]
So charge,q=It
q=5.28\ C
Therefore, the circuits X and Z deliver 5.64 C and 5.28 C of charge.
Hence, Bruce must include X and Z in his report.
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