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Find the coordinates of the turning point for the equation of the graph below
y=x^2– 16x +39
=

Respuesta :

Answer:

x = 8 - sqrt(y + 25)

Step-by-step explanation:

saharamagar2020

Step-by-step explanation:

comparing given equation with ax^2+bx+c;

a=1   b=-16   c=39

now,

x coordinate of vertex = -b/2a

                                      = 16/2*1

                                     = 8

again,

y coordinate of vertex = (8)^2-16(8)+39

                                       =-25

Therefore, the turning point is (8,-25).

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