What is the sum of the interior angles of this pentagon?
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[tex]sum\ or\ interior\ angles[/tex]
[tex]ol\ pentagon\ is\ 540\textdegree.[/tex]
[tex]Given\ of\ Pentagon[/tex]
[tex]To\ hind\ o\ sum\ of\ Interiur\ angle\ of[/tex]
[tex]pentagon.[/tex]
[tex]solutiono[/tex]
[tex]sum\ of\ the\ interior[/tex][tex]angler\ of\ a\ pentajon[/tex]
[tex]can\ be\ round\ by\ 1\ st[/tex]
[tex]dividing\ it\ into\ triangler[/tex]
[tex]from\ 1\ verter.[/tex]
[tex]\therefore\ There\ are\ 3\ Triangles\ made.[/tex]
[tex]sum\ of\ interiar\ angler\ or\ Triangles\ is[/tex]
[tex]180\textdegree.\ Tmere\ are\ 3\ Triangles.[/tex]
[tex]\therefore \ \ \ \ \ 180\times 3=540\textdegree.[/tex]
[tex]Hence\ sum\ ot\ interior\ angles[/tex]
[tex]ol\ pentagon\ is\ 540\textdegree.[/tex]
I hope this helps you
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