Answer:
B. 6π[tex]\sqrt{2}[/tex]
Step-by-step explanation:
If you look at the help image I attached, what we are given is in RED and what we solve is in BLUE.
First, draw a diagonal in the square. Its length is the diameter, but we don't know the exact value. Since two right triangles have been created, we use Pythagorean Therom to solve for the hypotenuse/diameter:
[tex]a^2+b^2=c^2\\6^2+6^2=c^2[/tex]
[tex]\sqrt{36+36} =c[/tex]
[tex]6\sqrt{2}=c[/tex]
If diameter = [tex]6\sqrt{2}[/tex], then radius is [tex]\frac{6\sqrt{2}}{2}[/tex] or [tex]3\sqrt{2}[/tex]
Circumference = 2πr
2π ([tex]3\sqrt{2}[/tex])
6π[tex]\sqrt{2}[/tex]
I hope this helps!
