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An electron in the n=7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 93.1 nm.
What is the value of n for the level to which the electron relaxed?

Respuesta :

yusranoor148

answer:

nf=2

Explanation:

It is given that,

Initially, the electron is in n = 7 energy level. When it relaxes to a lower energy level, emitting light of 397 nm. We need to find the value of n for the level to which the electron relaxed. It can be calculate using the formula as :

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