The distance the 100kg man must climb to burn off 500 kilocalories by running up an elliptical path is 2,136.1 m.
The potential energy of the man from a known height can be used to deternine the distance the man would have to climb.
P.E = mgh
Where;
P.E is potential energy, given as 500 kilocalories,
1 kcal = 4186.8 joules
500 kcal = 2,093,400 J
h = P.E/mg
h = (2,093,400) / (100 x 9.8)
h = 2,136.1 m
Learn more about potential energy here: https://brainly.com/question/1242059