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There are 9 balls numbered 1 through 9 placed in a bucket. What is the probability of reaching into the bucket and randomly drawing four balls numbered 6, 9, 8, and 7 without replacement, in that order? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Respuesta :

Using the permutation formula, as the order is important, it is found that there is a 0.000331 probability of selecting the balls in the desired order.

What is the permutation formula?

The number of possible permutations of x elements from a set of n elements is given by:

[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]

In this problem, 4 balls will be taken from a set of 9, hence the total number of outcomes is:

[tex]P_{9,4} = \frac{9!}{5!} = 3024[/tex]

The desired outcome is only one, hence the probability is given by:

p = 1/3024 = 0.000331.

There is a 0.000331 probability of selecting the balls in the desired order.

More can be learned about the permutation formula at https://brainly.com/question/25925367