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A compound has a mass percent composition of 58.8% C, 9.86% H and 31.32% O. The molar mass of the compound is 306.39 g/mol.

(a) Calculate the empirical formula.

(b) Calculate the molecular formula

Enter your answers using the following format for a formula: C3H3O3

Respuesta :

The solution would be like this for this specific problem:

Moles of carbon = 58.8 / 12 = 4.9

Moles of hydrogen = 9.8 / 1 = 9.8

Moles of oxugen = 31.4 / 16 m= 1.96

Ratio 4.9 / 1.96 = 2.5 9.8 / 1.96 = 5.0 1.96 / 1.96 = 1

Simplest formula = C5H10

I hope this helps and if you have any further questions, please don’t hesitate to ask again.

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