Using the standard normal form table to find the probability is; p(z ≤ 0.82) ≈ 0.7939
When talking about z-score in standard normal distribution, there could be greater than or equal to, less than or equal to, greater than, less than.
Now, in this case, we are dealing with the probability of p(z ≤ 0.82). This gives;
p(z ≤ 0.82) = 1 - 0.2061
p(z ≤ 0.82) = 0.7939
Thus, from normal form table, p(z ≤ 0.82) ≈ 0.7939
Read more about Standard tables at; https://brainly.com/question/4079902
