contestada

Suppose ABCD is a rectangle, F and G are points on





DC





such that





DF = GC, and





A(F) ∩ BG = E. Prove that DE = CE.






(I had to put parentheses around the F or else Brainly would think I'm swearing, just so you know. )

Respuesta :

batolisis

The two sides are equal and for that reason DE = CE as shown below :

AD = BC, DF = GC

E = A(F) and E = BG,  therefore A(F) = BF

Description of rectangle

Now we all know that a rectangle has four edges which are A, B, C, D.

when we divide the bottom line, which is the line from point C to D into three parts we will have ( DF, FG, and GC )

From the question we know that DF = GC

E is the intersection of A(F) and BG

we can now Prove that DE = CE.

since D and C are point included in E and since this is a rectangle

AD = BC, DF = GC

E = A(F) and E = BG,  therefore A(F) = BF

DE = CE

We can conclude by saying that in a rectangle two sides are equal and for that reason DE = CE

Learn more about Rectangle : brainly.com/question/22148953

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