Brahmagupta’s solution to a quadratic equation of the form ax2 bx = c involved only one solution. which solution would he have found for the equation 3x2 4x = 6?

Respuesta :

The value of the quadratic equation is given by the formula. Then the value of x is 0.8968 and negative 2.23.

What is a factorization?

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The equation for the expression is given below.

3x² + 4x = 6

3x² + 4x - 6 = 0

we know that the formula

[tex]\rm x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

Then we have

[tex]x = \dfrac{-4 \pm \sqrt{4^2-4*4*(-6)}}{2*3}\\\\x = \dfrac{-4 \pm \sqrt{112}}{6}\\\\x = 0.8968, \ -2.23[/tex]

More about the factorization link is given below.

https://brainly.com/question/6810544