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Two spheres have volumes of 8π cm3 and 64π cm3. if the surface area of the smaller sphere is 16π cm2, what is the surface area of the larger sphere? 64π cm2 96π cm2 128π cm2 256π cm2

Respuesta :

ashishdwivedilVT

The surface area of the larger sphere with a volume of 64π cm³ is 16π∛36 cm³.

The volume of the larger sphere = 64π cm³

let us take the radius of the larger sphere r

So, 4/3*π*r³ =64π

r³=48

r=2∛6

What is the surface area of a sphere?

The surface area of a sphere with radius r is 4πr².

So, the surface area of the larger sphere = 4π(2∛6)²

The surface area of the larger sphere = 16π∛36

Hence, The surface area of the larger sphere with a volume of 64π cm³ is 16π∛36 cm³.

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