The line that passes through (0 1) and (1 4) is a linear equation
The equation of the points is y = 3x + 1
The points are given as:
(x,y) = (0 1) and (1 4)
Start by calculating the slope (m)
m = (y₂ - y₁)/(x₂ - x₁)
So, we have:
m = (4 - 1)/(1 - 0)
Evaluate
m = 3
The equation is then calculated as:
y = m(x - x₁) + y₁
This gives
y = 3(x - 0) + 1
Evaluate the product
y = 3x + 1
Hence, the equation of the points is y = 3x + 1
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