3.75 N of force will be applied to a charge. Because of the electric field, a force operated on the charge.
The electric force between two charges is proportional to their product and inversely proportional to the square of their distance.
In this question, the provided data is:
F is the applied force,
q denotes the charge, which is equal to 2.5 C.
v is the velocity = 5.0 10³ m/s
B is the magnetic field = 3.0 10² T
The following is the force on a moving charge:
[tex]\rm F = q V B sin \alpha \\\\ F = 2.5 \times 10^{-6} \times 3 \times 10^{-2} \times 5 \times 10^3 \\\\ F=3.75 \ N[/tex]
As a result, 3.75 N will be exerted on a charge.
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