The Confidence Interval of the given random sample survey is gotten as; CI = 13.755 ± 1.456
We are given the hypotheses as;
Null Hypothesis; H₀: μ = 15
Alternative Hypothesis; Hₐ: μ ≠ 15.
where μ is the mean number of hours worked per week for all students at the college with part-time jobs.
We are told that it has a 95% confidence interval and degree of freedom of df = 25
From the t-table, the t-score = 2.06
The table gives us the standard error as 0.707 and sample mean of 13.755. Thus, we can find the confidence interval as;
CI = 13.755 ± 2.06(0.707)
CI = 13.755 ± 1.456
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