Calculate and compare the molar solubility of Mg(OH)2 in water and in a solution buffered at a pH of 4. 5. Required:

Determine the molar solubility of Mg(OH)2 in water and the pH of a saturated Mg(OH)2 solution

Respuesta :

Since Mg(OH)2 is a base, the molar solubility of Mg(OH)2 in water is less than in a solution buffered at a pH of 4.5

What is molar solubility of a solute?

The molar solubility of a solute is the amount in moles if a solute that dissolves in a given volume of solvent.

  • Molar solubility = moles of solute/volume of solvent.

Mg(OH)2 is a base which is partially soluble in water.

Molar mass of Mg(OH)2 is 58 g/mol

Moles of Mg(OH)2 can be calculated using the formula: moles = mass/molar mass

The pH of a solution of Mg(OH)2 will be greater than 7.

In a solution buffered at a pH of 4.5, the molar solubility of Mg(OH)2 will be greater than in water since more of the base can dissolve in acidic buffer solution.

Therefore, the molar solubility of Mg(OH)2 in water is less than in a solution buffered at a pH of 4.5

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