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A boy skips a rock so that it bounces off the water with a velocity of 3. 5m/s at 40. 0 degrees. How long will it take to hit the water again?

Respuesta :

oladayoademosu

Since the rock has a velocity of 3.5m/s at 40.0°, it will take the rock 0.46 s to hit the water again.

Since the rock is a projectile, we use the time of flight of a projectile to find the time it hits the water again

Time of flight of projectile.

The time of flight of the rock is given by T = 2UsinФ/g where

  • u = velocity of stone = 3.5 m/s,
  • Ф = angle of projection = 40.0° and
  • g = acceleration due to gravity = 9.8 m/s².

Substituting the values of the variables into the equation, we have

T = 2UsinФ/g

T = 2 × 3.5 m/s × sin40.0°/9.8 m/s².

T = 7.0 m/s × 0.6428/9.8 m/s².

T = 4.4995 m/s ÷ 9.8 m/s²

T = 0.459 s

T ≅ 0.46 s

So, it will take the rock 0.46 s to hit the water again.

Learn more about time of flight of projectile here:

https://brainly.com/question/24136952

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