Neither the laws of sines nor the law of cosines can be used to solve the triangle. The correct option is the third option - neither law can be used
Solving trianngles using the laws of sines & cosines
The law of sines is written as
[tex]\frac{sinA}{a}=\frac{sinB}{b}= \frac{sinC}{c}[/tex]
Where a,b, and c are sides of any given triangle and A,B, and C are the angles.
This law is used when we are given either
- Two angles and one side, or
- Two sides and a non-included angle
The law of cosines is written as
a² = b² + c² -2bc cosA, or
b² = a² + c² - 2ac cosB, or
c² = a² + b² -2ab cosC
Where a,b, and c are sides of any given triangle and A,B, and C are the angles.
This law is used when we are given either
- Three sides or
- Two sides and the included angle
Now, for triangle xyz, which the measures of angles X,Y, and Z are known, neither law can be used to solve the triangle.
Hence, neither the laws of sines nor the law of cosines can be used to solve the triangle. The correct option is the third option - neither law can be used
Learn more on Solving triangles using the laws of sines & cosines here: https://brainly.com/question/22339733
