The door's moment of inertia for rotation about a vertical axis inside the door, 14 cm from one edge is 4.205 kgm².
The door's moment of inertia for rotation about a vertical axis inside the door, 14 cm from one edge is calculated as follows;
[tex]I = I_{cm} + Md^2[/tex]
where;
[tex]d = \frac{L}{2} - 0.14\\\\d = \frac{0.91}{2} - 0.14\\\\d = 0.315 \ m[/tex]
[tex]I = \frac{1}{12} ML^2 + Md^2\\\\I = \frac{1}{12} (25)(0.91)^2 \ + \ (25)(0.315)^2\\\\I = 1.725 \ + \ 2.48\\\\I = 4.205 \ kgm^2[/tex]
Thus, the door's moment of inertia for rotation about a vertical axis inside the door, 14 cm from one edge is 4.205 kgm².
The complete question is below;
A 25kg solid door is 220 cm tall, 91 cm wide. What is the door's moment of inertia for rotation about a vertical axis inside the degr, 14 cm from one edge.
Learn more about moment of inertia here: https://brainly.com/question/14460640
