A stock solution has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L. What was the volume of the stock solution

Question

13-04-2022
Chemistry

contestada

A stock solution has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L. What was the volume of the stock solution

Respuesta :

Otras preguntas

Suppose that on the average, 7 students enrolled in a small liberal arts college have their automobiles stolen during the semester. What is the probability that

Why do you require an acid catalyst to make an ester? Why not just mix acid and alcohol? Describe an alternate method of making an ester that doesn't involve an

Which point is on the graph of f(x) = 2.5^x А. (1, 10) в. (0, 0) с. (0, 10) D. (10, 1)

Enviro Company issues 8%, 10-year bonds with a par value of $250,000 and semiannual interest payments. On the issue date, the annual market rate for these bonds

A superball and a clay ball are dropped from a height of 10cm above a tabletop. They have the same mass 0.05kg and the same size. The superball bounces off the

Factor completely 3x² − x − 4. 20 for the top answer

Find the measure of angle Z

Which statement describes the representation of the LQBTQ community in the media LGBTQ roles have become less common and diverse LGBTQ roles have become more co

Acromegaly a. occurs as result levels of sustained levels somatotropin b. occurs before fusion of epiphyseal growth plates c. is characterized by abnormally tal

How many bonds are present in Cl20? a. 2 b. 4 c. 1 d. 3

samueladesida43 samueladesida43 · Answer 1 · 2022-04-20T10:13:19+02:00

The volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.

How to calculate volume?

The concentration of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentration = 1.5M
C2 = final concentration = 0.54M
V1 = initial volume = ?
V2 = final volume = 0.18L

1.5 × V1 = 0.54 × 0.18

1.5V1 = 0.0972

V1 = 0.0972 ÷ 1.5

V1 = 0.065L

Therefore, the volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.

Learn more about volume at: https://brainly.com/question/1578538