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Part 1
Titrant (NaOH) concentration: 0.1 m NaOH

Vinegar volume: 2.0 mL vinegar

Initial buret reading (initial NaOH volume): 0.0 mL

Final buret reading (final NaOH volume): 17.7 mL

Calculate the moles of NaOH using the volume and molarity of NaOH.

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work. moles = molarity. volume (in Liters).


1.77 moles
17.7 moles
0.177 moles
0.00177 moles

Part 2

Part 1 Titrant NaOH concentration 01 m NaOH Vinegar volume 20 mL vinegar Initial buret reading initial NaOH volume 00 mL Final buret reading final NaOH volume 1 class=

Respuesta :

Oseni

The moles of NaOH used in the titration would be 0.00177 moles while the molarity of the vinegar will be 0.885 M

Titration calculation

Recall that: mole = molarity x volume

In this case, the molarity of the NaOH= 0.1 M

Volume of NaOH = 17.7 - 0.0 = 17.7 mL

Mole of NaOH used = 0.1 x 17.7/1000 = 0.00177 moles.

Since NaOH and vinegar have 1:1 mole ratio, the mole of vinegar will also be 0.00177 moles.

Molarity of vinegar = mole/volume = 0.00177/0.002 = 0.885 M

More on titration calculations can be found here: https://brainly.com/question/9226000

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