Hannah is experimenting with a new drawing program on her computer. She created quadrilateral MATH with coordinates M(1, 2). A(-5, 3), T(- 6,-3), and H(0,- 4). Hannah believes that she has created a square. Prove that Hannah is correct.

Hannah is experimenting with a new drawing program on her computer She created quadrilateral MATH with coordinates M1 2 A5 3 T 63 and H0 4 Hannah believes that class=

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The square MATH has equal side lengths MA, TH, AT and HM

Hanna's claim is correct because

  • The side lengths are equal.
  • Opposite sides have the same slope
  • The slopes of adjacent sides are opposite reciprocals

How to prove that Hannah is correct?

The coordinate points are given as:

M(1, 2), A(-5, 3), T(-6,-3), and H(0,- 4).

Calculate the side lengths of the square using the following distance formula

d = √[(x2 - x1)^2 + (y2 - y1)^2]

So, we have:

MA = √[(1 + 5)^2 + (2 - 3)^2] = √37

AT = √[(-5 + 6)^2 + (3 + 3)^2] = √37

TH = √[(-6 + 0)^2 + (-3 + 4)^2] = √37

HM = √[(0 - 1)^2 + (-4 - 2)^2] = √37

The side lengths are equal.

Next, we calculate the slopes using:

m =(y2 - y1)/(x2 - x1)

So, we have:

MA = (2-3)/(1+5) = -1/6

AT = (3+3)/(-5+6) = 6

TH = (-3+4)/(-6+0) = -1/6

HM = (-4-2)/(0-1) = 6

See that opposite sides have the same slope

i.e MA = TH and AT = HM

And adjacent sides have their slopes to be opposite reciprocals

i.e. MA = -1/AT and TH = -1/HM

The calculated distances and slopes implies that Hanna's claim is correct

Read more about quadrilaterals at:

https://brainly.com/question/3050890