For an aluminum disk of radius 8.7 cm and thickness 3.0 mm spinning around, moment of inertia is mathematically given as
I=16268.20gcm^2
What is the moment of inertia?
Generally, the equation for the volume is mathematically given as
v=\pir^2t
Therefore
v=\pi(8.7)^2*0.32
v=76.09cm^3
In conclusion, The inertia
I=136.83*8.7^2/2
I=16268.20gcm^2
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