[tex]x - 2y > - 12[/tex]
[tex] - 2y > - x - 12[/tex]
[tex]2y < x + 12[/tex]
[tex]y < \frac{x}{2} + 6[/tex]
[tex]plot \: the \: line \: of \: eq \: y = \frac{x}{2} + 6[/tex]
Now to find the solution for the inequality, let's substitute 1 point in the inequality.
Consider O(0,0)
[tex]0 < \frac{0}{2} + 6[/tex]
[tex]0 < 6 \\ true[/tex]
The region that contains the point O(0,0) is the accepted part.
Your answer is the last/first one.
