Answer:
d). (2m-1)(5m+3)
e). (2x-5)(2x-5)
f). (6n-4)(n+5)
Step-by-step explanation:
Solving by factorisation...
d). 10²+m-3
=> 10m²+6m-5m-3
=> 2m(5m+3)-1(5m+3)
=> (2m-1)(5m+3)
e). 4x²-20x+25
=> 4x²-10x-10x+25
=> 2x(2x-5) -5(2x-5)
=> (2x-5)(2x-5)
f). 6n²-20+26n
=> 6n²+26n-20
=> 6n²+30n-4n-20
=> 6n(n+5)-4(n+5)
=> (6n-4)(n+5)
